Sample Exam IV Solution v3 - Department of Chemistry CHM...

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Department of Chemistry CHM 1220/1225 Exam IV – Sample Exam – Solution 1. a. 3 3 3 6 2 c ] ][NO O) [Al(H + = K Liquids and solids are omitted. b. K a > 1000; at equilibrium the mixture will contain mostly products. c. This involves comparing K c to Q (initial concentrations). The reaction is COCl 2 ( g ) Æ CO( g ) + Cl 2 ( g ) [ ] [ ] [ ] 3 - 3 - 2 2 c 10 x 1.2 ) (0.755 ) )(0.030 (0.030 Q ; 10 x 3.8 COCl Cl CO = = = = M M M K K c > Q, so reaction proceeds forward.. 2. For the reaction CO 2 ( g ) + H 2 ( g ) ' CO( g ) + H 2 O( g ), K c =0.0667. Calculate the equilibrium concentration of CO if the initial concentration of [CO 2 ]=[H 2 ]=1.50 M. CO 2 + H 2 ' CO + H 2 O Initial 1.50 1.50 0 0 Change -x -x +x +x Equilibrium (1.50 – x) (1.50 – x) x x [ ] [ ] [ ][ ] ( ) ( ) x) - (1.50 x 0.258 x 1.50 x 0.0667 x 1.50 x 0.0667 H CO O H CO 2 2 2 2 2 2 2 c = = = = K 0.258(1.50 – x) = x 0.387 – 0.258x = x 0.387 = 1.258x x = 0.307 M = [CO] 3. For the endothermic reaction CO 2 ( g ) + H 2 ( g ) ' CO( g ) + H 2 O( g ) predict the direction the reaction will proceed in each of the following cases by circling the correct answer: a. Add CO 2 gas FORWARD REVERSE NO CHANGE b. Remove H 2 gas FORWARD REVERSE NO CHANGE c. Add CO gas FORWARD REVERSE NO CHANGE d. Remove H 2 O gas FORWARD REVERSE NO CHANGE e. Decrease the volume of the container FORWARD REVERSE NO CHANGE f. Increase the temperature FORWARD REVERSE NO CHANGE 4. Given the following equilibrium for the exothermic reaction: Co(H 2 O) 6 2+ ( aq ) + 4 Cl ( aq ) <==> CoCl 4 2– ( aq ) + 6 H 2 O( l ) pink blue What would you expect to see in each of the following situations?
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