Solution Q1 Test 2 - 8th May.pdf - Solution Q1 Test 2(8th May 2017 a b a Two categories of the conversion processes 1 Generation of mechanical energy to

Solution Q1 Test 2 - 8th May.pdf - Solution Q1 Test 2(8th...

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Solution Q1 Test 2 (8 th May 2017) a) a) Two categories of the conversion processes 1) Generation of mechanical energy to rotate electrical generator. 2) Direct conversion of non-electrical energy into electrical energy with the aid of energy storage components such as batteries. [4] b) i) Phase voltage at the sending end, V S , ? = (0.3 + ?0.4)×100 ?? = 30 + ?40 = ?? ∠??. ??° ? = ?2.0 ×10 −6 ×100 ?? = ?2.0×10 −4 = ?×?? −? ∠??° 𝐒 𝑉 ? = 110 × 10 3 √3 = ?????. ? ∠?° 𝑽 𝐼 ? = 20×10 6 √3 ×110×10 3 ×0.9 ∠ − ??? −1 0.9 = ???. ? ∠ − ??. ??° 𝑨 Phase voltage at the sending end, V S , 𝑉 ? = [1 + ?? 2 ] 𝑉 ? + ?𝐼 ? = [1 + (2×10 −4 ∠90°)(50∠53.13°) 2 ] 63508.5∠0° + (50∠53.13°)(116.6 ∠ − 25.84°) = 63508.5∠0° + 317.5∠143.13° + 5830∠27.29° = 63508.5 + ?0 − 254 + ?190.5 + 5181.1 + ?2673 = 68435.6 + ?2863.5 = ?????. ?∠?. ?° 𝑽 Line voltage at sending end, V SL , 𝑉 ?𝐿 = √3 𝑉 ? ∠2.4 + 30° = ???. ??∠??. ?° 𝒌𝑽 [1/2] [1/2] [1/2] [1/2] [1] [1]
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ii) Phase current at the sending end, I S 𝐼 ? = [? + ? 2 ? 4 ] 𝑉 ? + [1 + ?? 2 ] 𝐼 ? = [(2×10 −4 ∠90°)(63508.5∠0°) + ( (2×10 −4 ∠90°) 2 (50 ∠53.13°)(63508.5∠0°) 4 )] + [(116.6 ∠ − 25.84°) + ( (2×10 −4 ∠90°)(50 ∠53.13°)(116.6 ∠−25.84°) ? )] = 12.7∠90° + 0.032∠233.13° + 116.6∠ − 25.84° + .583 ∠117.29° = ?12.7 − 0.02 − ?0.03 + 104.9 − ?50.8 − 0.27 + ?0.52
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