Lect11Sep19F11

Lect11Sep19F11 - General Chemistry I Chemistry 177 Lecture...

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1 “General Chemistry I” Chemistry 177 Lecture #11 Monday September 19, 2011 NEXT LECTURE: Read BLBMW Sections 4.4- 4.6 Please take out your CLICKERS and CALCULATORS MylabsPLus ASSIGNMENT #5: Due September __ at midnight EOC HOMEWORK: Thursday 9/22 in Recitation Chapter 3: 33, 35, 37, 39, 43, 46, 49, 51, 53, 61, 63, 65, 67 Quiz #5 In recitation on Thursday Clicker: “GO 17 GO” -or- “CH 17 CH” when asked to do so during the lecture Please show respect to your colleagues: Turn off cell phones, put aside the Daily , do not use iPods, laptops, or other PDAs for messaging, facebook, internet browsing, etc. during lectures and recitations.
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Limiting Reagent Problems 2
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Do You Understand Limiting Reagents? In one process, 124 g of Al are reacted with 601 g of Fe 2 O 3 2Al + Fe 2 O 3 Al 2 O 3 + 2Fe Calculate the mass of Al 2 O 3 formed. 3.9
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In one process, 124 g of Al are reacted with 601 g of Fe 2 O 3 2Al + Fe 2 O 3 Al 2 O 3 + 2Fe Calculate the mass of Al 2 O 3 that can form if all of the Fe 2 O 3 reacts. g Fe 2 O 3 mol Fe 2 O 3 mol Al 2 O 3 g Al 2 O 3 601 g Fe 2 O 3 1 mol Al 2 O 3 1 mol Fe 2 O 3 x 383 g Al 2 O 3 Start with 601 g Fe 2 O 3 could make 383 g Al 2 O 3 Do we have enough Al to react with all of the Fe 2 O 3 ? 3.9
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This note was uploaded on 10/02/2011 for the course CHEM 177 taught by Professor Greenbowe during the Spring '06 term at Iowa State.

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Lect11Sep19F11 - General Chemistry I Chemistry 177 Lecture...

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