Exer 4-24

Exer 4-24 - Exercise 4.24 Solution Multiply differential...

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Exercise 4.24 Solution ( ) ( ) [ ]{ } { } [ ] { } = = = = = α = = + = + = = + + + α = = + α = + = = = = = + ψ α = ψ ψ = = = α + = α + 0068 . 0 0057 . 0 0033 . 0 MATLAB using Solution 01121 . 0 0216 . 0 0216 . 0 5 . 10 5 . 10 24 0 5 . 13 30 60 , 10 , / 10 12 , / 10 30 Using 0 , 400 : Conditions Matching and Boundary 1 2 2 20 20 5 6 20 5 6 5 2 12 0 20 3 6 5 12 become equations condensed the 0, with elements finite linear three using problem bar For the 1 1 20 , 1 1 1 1 20 2 6 0 , 10 6 ) ( and : functions ing approximat linear Using ] ) ( [ , matrices with equation element to reduces form weak scheme, Galerkin - Ritz Using term loading d distribute with
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This note was uploaded on 10/03/2011 for the course MCE 561 taught by Professor Sadd during the Spring '11 term at Rhode Island.

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