Exam3_S2004 - 1 Exam #3, CHEM112, S04 Name:

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Unformatted text preview: 1 Exam #3, CHEM112, S04 Name: __________________________________________ Social Security Number: ______________________________ Show all work!!! Circle the final answer in each problem!!! R = 0.0821 L•atm/mol•K = 8.314 J/mol•K 1 L• atm = 101.3 J w = -P ∆ V PV = const if T = const q surr = C ∆ T q surr = -q system ∆ E = q + w ∆ H = ∆ E + P ∆ V if P = const ∆ H = ∆ E + ∆ nRT ∆ G = ∆ H - T ∆ S ∆ G = ∆ G° + RTlnQ ∆ G° = -RTlnK eq K eq = e- ∆ G°/RT lnK eq = ∆ S ° R − ∆ H ° RT aA + bB cC + dD rate = − ∆ [A] a ∆ t = − ∆ [B] b ∆ t = + ∆ [C] c ∆ t = + ∆ [D] d ∆ t rate = k[A] x [B] y------------------------------------------------------------- rate = k[A] 0 [A] = [A]-kt ------------------------------------------------------------- rate = k[A] 1 [A] = [A] e-kt ln[A] = ln[A] – kt t 1/2 = 0.693/k -------------------------------------------------------------- rate = k[A] 2 1 [A] = 1 [A] + kt ---------------------------------------------------------------...
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This note was uploaded on 10/03/2011 for the course CHEM 112 taught by Professor Chen during the Spring '09 term at South Carolina.

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Exam3_S2004 - 1 Exam #3, CHEM112, S04 Name:

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