This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: le (txl65) – Homework 4 – Spurlock – (11881) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A 2 . 7 kg object hangs at one end of a rope that is attached to a support on a railroad boxcar. When the car accelerates to the right, the rope makes an angle of 46 ◦ with the vertical The acceleration of gravity is 9 . 8 m / s 2 . a 2 . 7 kg 4 6 ◦ Find the acceleration of the car. ( Hint: vectora object = vectora car ) Correct answer: 10 . 1482 m / s 2 . Explanation: Given : m = 2 . 7 kg , θ = 46 ◦ , and g = 9 . 8 m / s 2 . T T sin θ T cos θ θ m g Vertically summationdisplay F y = T cos θ- m g = 0 T cos θ = m g . (1) Horizontally, summationdisplay F x = T sin θ = m a . (2) Dividing Eqs 1 and 2, we have T sin θ T cos θ = a g tan θ = a g a = g tan θ = ( 9 . 8 m / s 2 ) tan 46 ◦ = 10 . 1482 m / s 2 ....
View Full Document
This note was uploaded on 04/05/2011 for the course SD ds taught by Professor Sdsd during the Spring '11 term at Tarrant County.
- Spring '11