3343 T1 02 (2)

3343 T1 02 (2) - saline solution is given as 0.9%...

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Quantitative Analysis Spring 2002 Test I I. Calculate the molarity and the uncertainty in a solution prepared by dissolving 6.173 ± 0.005 g of KCI (75.56) (purity 99,2 ± 0.2%) in water to obtain a final volume of 100.00 ± 0,06 mE. (10) 2. (2X) A student analyzed an unknown sample of KHP and obtained the following percentages as results: 31,24, 31,44, 31.32, 31.22, 31.34, 31,29 and 31,27. Calculate the mean, standard deviation, relative standard deviation and the 95% confidence interval for this data. (20) 3. Can any of the above values be rejected at the 95% confidence level? (10) 4, A student analyzed a second sample of KHP by the same method as in problem 2 and from four analyses a mean of 31.37% was obtained. Is there any indication that the two samples were different? (15) 5. Isotonic saline drips used in the hospitals must have the same osmotic pressure as the normal body fluids. If the
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Unformatted text preview: saline solution is given as 0.9% NaCl,(58.4) what is the molarity of the solution. (9) 6, What are the sources of determinant error and how do you compensate for them?(l0) 7. If the density of 70.5% HCIO 4 solution is 1.67 g/mL, what is its molarity? (9) 8. If the K sp of Hg 2 CI 2 is 1.2 x 10-18 , what would he the expected [Hg 2 2 ] in the human stomach from someone who ingested Hg 2 Cl 2 . Remember the stomach is approximately 0.01 M in HCI. (We are ignoring all complexation.) (9) 9, Given the following equilibria calculate the value of Keq for the reaction AgCl(s) + 2 NH 3 (aq)= Ag(NH 3 ) 2 + + Cl-. (all ions are in solution) (8) AgCl(s) =Ag + + Cl-Ksp = 12.8 x 10-10 and Ag + + 2 NH 3 = Ag(NH 3 ) 2 + Kf= 2.5 x l0 7...
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