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Nair-Rejesh-Exam1(2)

# Nair-Rejesh-Exam1(2) - Problem 1 2 3 4 5 Earned 14 17 20 19...

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Problem Value Earned 1 20 14 2 20 17 3 20 20 4 20 19 5 20 18 Total 100 88 1) Assume you have a list of 1,000,000 people and you wish to take a random sampl Show how you would take the sample and place the results below. (Assume the list 1,000,000 which is the person's ID and the second with the person's name). All you Sample ID 1 2 3 4 5 6 7 8 9 10 Ans: Step 1: ASSIGN THE RANDOM NUMBERS Sample ID 1 0.22 2 0.82 3 0.42 4 0.18 5 0.12 6 0.06 7 0.06 8 0.91 9 0.69 10 0.59 Step 2: FREEZE THE VALUES Sample ID

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1 0.06 2 0.97 3 0.43 4 0.08 5 0.52 6 0.19 7 0.72 8 0.91 9 0.1 10 0.29 Step 3: SORTING THE NUMBER BY RANDOM NUMBER VALUE Sample ID 1 0.06 4 0.08 9 0.1 6 0.19 10 0.29 3 0.43 5 0.52 7 0.72 8 0.91 2 0.97 MY RANDOM NUMBER WITHPUT REPLACEMENT CONSISTS OF THE 10 H
le, without replacement, of 10 names from this list. consists of two columns, one with a number from 1 to u have to show below is the ID numbers selected. you need to pick 10 names form 1000000. you did not do this Minus six

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HIGHLIGHTED NUMBERS OR IDS
2) The following data shows the number of hours worked by 50 middle mangers during 47 50 52 55 46 50 53 49 43 48 51 54 52 47 49 45 51 53 49 47 52 61 50 51 53 49 50 45 55 51 52 46 47 50 48 57 50 48 55 49 53 49 54 44 47 51 45 51 50 52 a) Find the arithmetic mean of this data: 50.12 b) Find the median of this data: 50.00 c) Find the standard deviation of this data: 3.48 d) Construct a Histogram of this Data using intervals starting at 40 and increasing by 5 u BINS FREQUENCY 40 0 45 5 50 23 55 20 60 1 65 1 mi fi Interval Mid point Freq Cumulative f(i)*m(i) f(i)*m(i)*m( 40 45 42.5 5 5 212.5 9031.25 45 50 47.5 23 28 1092.5 51893.75 50 55 52.5 20 48 1050 55125 55 60 57.5 1 49 57.5 3306.25 60 65 62.5 1 50 62.5 3906.25 50 2475 123262.5 MEDIAN USING THE COLUMN IT IS CLEAR THAT 25th value lies in the interval 45-50 we estimate the 25th value = 49. = x = med x ~ = s

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26th value lies in the interval 45-50 we estimate the 26th value = 49. therfore median = 49.34+49.56/2 e) Find the arithmetic mean using the grouped data only: (I.e. pretend you don't have the raw data, just the histogram) f) Find the median using the grouped data only: g) Find the standard deviaiton using the grouped data only: h) Comment on how the values compare.
g a one week period. 28 48 49 50 until the value of 65. (i) 45+(5/23)*20 49.34 0 5 10 15 Histogram BINS Frequency 0 5 10 15 Histogram B Frequency

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45+(5/23)*21 49.56 2=49.45 Im not able to draw the histogram as my ex ansewers to f and g are just numbes and not computed on sheet as instructed minus three 49.5 49.45 3.91 S^2=(fi*mi^2-nx^2)/(n-1) nx^2 122512.5 fi*mi^2-nx^ 750 s^2= 15.31 s= 3.91 = x = med x ~ = s
Column M 0 5 10 15 Histogram C BINS Frequency m Column N BINS 0 5 10 15 Histogram Column S Frequency

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xcel is not working. BINS
Column U

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3) You may have noticed how close people follow each other on the expressways in t area. The following data was collected relating stopping distance and speed. It was using very alert drivers with new tires on dry pavement. Determine the relationship b stopping distance (y) and speed (x). Make sure you check the residuals for randomn (Hint: If your residuals don't look random try adding a square term for x to your mod Then regress on both x and xsquared simulataneously (multiple regresssion)).

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