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Assignment 5 Solutions

Assignment 5 Solutions - Assignment 5 Start Date 1 New 2008...

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Unformatted text preview: Assignment 5 Start Date: 1? New 2008 at 08:00 AM 3 Dec 2008 at 11:00 PM Student Access after Due Date: Yes. 1-.i"iew With Assistance Graded: Yes _ Chapter 12, Problem 30 GO _ In Figure 12-46,. suppc-se the length 1'. cf the unifprm bar is 3.4 m and its weight is 180 N. Alsp, let the hlc-ck's weight W = 320 N and the angle El = 39". The wire can withstand a maximum tensipn at 450 N. We place the hlc-cl-s: at distance x that creates that maximum tensicn in the wire. What is the value at: x? I; t 1.3. on. hum “Aurmn‘n LP“- WIK °\ \\-c".~0k0\“ L‘Fw. r\ “C , - . u nu'm u ’7; ‘- u C: r ,_ - ‘ o '. " t. o l: C " - \a) —- -~ :01 AA —". .lls -, —7Cl/J ’ L2, w- + LTm9 =0 , - L7 1 _ A = L 193‘» — l 17 L;— A = 3"‘l HCOA) ) 9 - i (ON) T- 2.0 m Chapter 15, Problem 36 GO In Fig. 15-40,. block 2 of mass 2.?0 l-cg oscillates on the end of a spring in SHM with a period of16.00 ms. The position of the block is given by x = {1.50 cm) cos{o.rt + #2}. Block 1 of mass 5.40 kg slides toward block 2 with a velocity of magnitude 4.00 mfs, directed along the spring's length. The two hlocl-cs undergo a completelyr inelastic collision at time t= 4.00 ms. {The duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision? L‘ ‘ rA -' l A. l ’ A 3% H- at! M\ A l A q A N: M" (In A. A Am, . E- A .- “at L". C. l A «pr‘ _ A c A pr‘a ‘ l\ ' I\ ' 1‘ l ‘ ‘-~ AA-uu" AA. 4 _ 0L “A . u l' 2 2 l5— 7' 2: u 59" = M 7:; 2.1 T T” = LlTT-L 35h) "lvlul Mar N l... '3 L T1 A. l I_' v \‘ (a AA._ 11 . l a \. m .4 n . l/u alum-BL Ill- AA ‘ ‘4- 4.. l A ‘ A.‘ C t .77) CM 'b + Tl" 1 764. I A - Ac ‘ 3 l 1 32.3— Fouls. 7 A = Qua A. wlm . " , lot. 7- ; 0x 1(‘loUXlqu 2mm 6.23 w- 32.1 +1Tz, w '3) 7, —. — ('5‘?) M V (301’ :‘ \rc = Ax ~ -' J ‘6‘— LLo n. C '9 n. 7' A! 5"] 4 [A . A' ‘ L . mu- _ I' A \ AA A :Uk 0‘ ) 7% Am ‘ ‘ TLL A ‘ u. 5‘ v a 0 ‘ u A , m‘ A m._ I I \ ‘NA .1. 1. ‘.. ‘ A . A“: _ u S E: + (A ’L = + t 0‘ d -. I I * 111 Phil. | 0‘... ‘A A4} A N A I ‘h _+ L 14% ’M x l")— _/J‘ ) Pr: 1 PM 7' 1— = 7'0“ 70“ k. V cc +m _(<. mm» m— am 2 in 4.1-? ) w st) : ("0i .4 ' A.“ I. A ‘A ‘ A : laq Chapter 16, Problem 52 A standing wave pattern on a string is described bv ytx, t) = 0.044 sin {Enletcos Edntj, where x and y are in meters and t' is in seconds. For x 2 El, what is the location of the node with the [a] smallest, [h] second smallest, and [1:] third smallest value of x? [d] What is the period of the oscillatoryr motion of anv {nonnode} point? What are the [a] speed and [f] amplitude of the two traveling waves that interfere to produce this wave? For t! El, what are the [9] first, [h] second, and [i] third time that all points on the string have zero transverse velocitv? (“I A (N. l ’6‘! [A A I ( ‘ , | ' I W A“ A A 14 “n J- ‘r- ’ .A’I 1 ’ I I (x -— ‘n . I I A .4 : 0'011 M C 2 ,‘ a AA D ' ' 'A' v m i - A ’ Pl I; ‘4- Cr ‘O’A . U Q \ ”Lu A 4 \ ' I'\ r) x - zr ML 2 MIL ll». _ “(“0 (MIL . ‘I z A 7— ’l b I‘ A. Y r‘ on I) K g 1‘ m Z 8’ _ Zr (4) Hi- M h a 3). 5 ‘ ‘ ‘ (”d/V [It ‘ 4‘ \‘l/ f' _n.; _ AA [A \ l ‘A t T— o S. L > -' - > \ I A 4.‘A I 1. Z .3 I Z . Chapter 1?, Problem 50 GO Pipe A, which is 1.60 rn long and open at both ends, oscillates at its third lowest harmonic frequency. It is filled with air for which the speed of sound is 343 mfs. Pipe 3, which is closed at one end, oscillates at its second lowest harmonic frequency. This frequency of El happens to match the frequency of A. An .1: axis extends along the interior of B, with x = [I at the closed end. What is the second smallest value of x at which a node is located in B? \ r- “lo- ‘ ‘4‘ 4 0 “ J'A. A - A. 'u « L ‘ . I \ : HT I \ 1.. Q =— \ I'l‘ A4 if“ od— A, ‘.r~ Ar. u " b L 1" b I 5 \ n- C. It: '0‘. ’ A AA‘ JA- (i "p’ A 0k be. “A“ u A 3 A. 'A n61 W1. l (I) § I —= =1 ~ _ at In, ._ _ ‘ ~ I (“warn ‘— I 2 L m + L’ ‘ -m\n ”mg: -\' “mi-M? vrfv— _ Chapter 1?, Problem 58 A stationaryr motion detector sends sound waves of frequencyr [1.159 MHz toward a truck approaching at a speed of 43.5 rnfs. IWhat is the frequencyr of the waves reflected back: to the detector? {Take the speed of sound to be 343 rnr’s.) Let's 4" POLO l ML) A. II'\ ‘4 . puns -' 0\ lump. :- _. .1 a H- 1‘ My.‘ A ‘ “Uk— _ “A - AA Al'a- ”A 1- Ah 3‘ L! 9k 'ul /L444 A _ I 1 A. P A A Afl — A _ 5‘4. .4 5' ‘— + 0‘ (ho Mm ‘p‘ Mud ll. f Mfil‘w ‘LIUI'JJ ) A 4‘ A4 ' 1- JA . A A A 7 'A I / 6 ‘ M§ . A , ¥ ‘_ r ‘ A l' D I h v A‘..- A Lh'... A A 1l I , 'C '3 1‘. V‘- A A AA -’ a / IAL 0'. I 11 . Au l A I I > £ (J"§U~ V‘ : U? V! ——-. tr U’V‘ «(1‘ . g3" 4’ 3J- ...
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