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Unformatted text preview: th step of the giant list and the 16 th step of the baby list. We can therefore write 2 16 329*284*62 (mod 6917) which implies that 2 5224 329(mod 6917) and so the solution for x is 5224. This can be verified directly now. So we can get j=16 k=62 2 16+84*62 329 (mod 6917) So we get 21 5224 329 (mod 6917) The Maple routine looks like this: ) 6917 (mod 2 * 329 2 84 k j ) 6917 (mod 329 2 84 k j > >...
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This note was uploaded on 10/03/2011 for the course SIT 281 taught by Professor Vickymak during the Three '09 term at Deakin.
 Three '09
 VICKYMAK

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