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Unformatted text preview: 0.8640539 0.9068448 sample estimates: p 0.8871753 99%: Rweb:> prop.test(x=1093, n=1232, conf.level=0.99) 1sample proportions test with continuity correction data: 1093 out of 1232, null probability 0.5 Xsquared = 737.1826, df = 1, pvalue < 2.2e16 alternative hypothesis: true p is not equal to 0.5 99 percent confidence interval: 0.8614137 0.9087171 sample estimates: p 0.8871753 d) The higher the confidence level is, the wider the confidence interval will be. c) This data must be obtained randomly, based on the text, we can assume that. In addition, the number of success and failures must be larger than 15, which is OK here, too. 2 3...
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This note was uploaded on 10/02/2011 for the course STAT 3011 taught by Professor Wang,zhan during the Spring '09 term at Minnesota.
 Spring '09
 WANG,ZHAN
 Probability

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