# HW7Sol - 0.8640539 0.9068448 sample estimates: p 0.8871753...

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STAT 3011 HW 7 Solution Instructor: Alicia Johnson Rweb:> prop.test(x=1093, n=1232, conf.level=0.95) 1-sample proportions test with continuity correction data: 1093 out of 1232, null probability 0.5 X-squared = 737.1826, df = 1, p-value < 2.2e-16 alternative hypothesis: true p is not equal to 0.5 95 percent confidence interval: 0.8678598 0.9040288 sample estimates: p 0.8871753 1

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c) 98%: Rweb:> prop.test(x=1093, n=1232, conf.level=0.98) 1-sample proportions test with continuity correction data: 1093 out of 1232, null probability 0.5 X-squared = 737.1826, df = 1, p-value < 2.2e-16 alternative hypothesis: true p is not equal to 0.5 98 percent confidence interval:
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Unformatted text preview: 0.8640539 0.9068448 sample estimates: p 0.8871753 99%: Rweb:> prop.test(x=1093, n=1232, conf.level=0.99) 1-sample proportions test with continuity correction data: 1093 out of 1232, null probability 0.5 X-squared = 737.1826, df = 1, p-value < 2.2e-16 alternative hypothesis: true p is not equal to 0.5 99 percent confidence interval: 0.8614137 0.9087171 sample estimates: p 0.8871753 d) The higher the confidence level is, the wider the confidence interval will be. c) This data must be obtained randomly, based on the text, we can assume that. In addition, the number of success and failures must be larger than 15, which is OK here, too. 2 3...
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## This note was uploaded on 10/02/2011 for the course STAT 3011 taught by Professor Wang,zhan during the Spring '09 term at Minnesota.

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HW7Sol - 0.8640539 0.9068448 sample estimates: p 0.8871753...

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