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Exam_2A - BioS 115 Genetics Exam 2 Version A Name I M P O R...

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BioS 115 Exam 2 Version A _______________________ Genetics October 25, 2010 Name Page 1 of 5 IMPORTANT: Mak e s ur e you hav e your s c an t ron . Wri t e t h e e xam v e r s ion (A , B , C) on t h e an s w e r c ard! Wri t e your nam e on t hi s s h ee t . Th e r e ar e 45 qu e st ion s on t h e e xam , wor t h a t o t al of 90 poin ts . Pl e a s e r e ad t h e qu e st ion s c ar e fully . Alway s c hoo s e t h e MOST CORRECT an s w e r . Mark an s w e r s on t h e e xam s h ee t F IRST . Wh e n you ar e c onfid e n t t ha t your an s w e r s ar e c orr ec t , mark t h e s c an t ron s h ee t u s ing a No . 2 p e n c il . Thi s st ra t e gy avoid s e ra s ur e s on t h e s c an t ron s h ee t . Bo t h t h e e xam and s c an t ron s h ee ts will b e c oll ec t e d . 1. The maximum recombination frequency between two genes is A) 100% B) 60% C) 50% D) 10% E) 1% 2. A phenotypically normal couple has a phenotypically normal daughter and a son who suffers from a X-linked, recessive disease with strong phenotype. What is the probability that the daughter is a carrier of the disease gene? (applies to questions 3 and 4): Albinism is a total lack of skin pigment due to an autosomal, recessive gene. What is the probability of a couple having an albino child if: 3. She is albino, he is normally pigmented but his father was albino. 4. Both are normally pigmented as are their parents, but both have albino siblings. 5. The most common form of color blindness in human beings results from an X-linked recessive gene. A phenotypically normal couple has a normal daughter and a son who is color blind. What is the probability that the daughter is heterozygous? A) 1/8 B) 1/4 C) 1/2 D) 2/3 E) 3/4 _ (6) __ is the occasional failure of two chromosomes to separate from each other during meiosis. _ (7) __ is a human genetic disease caused by such an event involving the X chromosome. 6. 7. A) albinism B) hemophilia C) alkaptonuria D) Klinefelter syndrome
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