problem02_21 solution

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.21: a) Equating Equations (2.9) and (2.10) and solving for v 0 , . s m 00 . 5 s m 0 . 15 s 00 7 m) 70 ( 2 ) ( 2 0 0 = - = - - = . v t x x v x x b) The above result for v 0 x may be used to find , s m 43 . 1 s 00 . 7 s m 00 . 5 s m 0 . 15 2 0 = - = - = t v v a x x x or the intermediate calculation can be avoided by combining Eqs. (2.8) and (2.12) to
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Unformatted text preview: eliminate v x and solving for a x , . s m 43 . 1 s) 00 7 ( m . 70 s 00 . 7 s m . 15 2 2 2 2 2 = -= --= . t x x t v a x x...
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