This preview shows page 1. Sign up to view the full content.
Unformatted text preview: to use 1/2 the steel in each direction so A s = 2(1.27 in 2 ) which would reduce P u . (Remember f s can not be greater than 60 ksi, so that P nx = 620.3 k and P ny = 578.4 k P n = 360.7 k and P u = 234.5 k ) Go back and prove the numbers for the last assumption for biaxial loaded column Determine the load capacity of the column, if the eccentric loading is at e x = 5.5 in. and e y = 8 in. and f c = 4 ksi and f y = 60 ksi...
View Full Document
- Summer '08