Unformatted text preview: the mean and median.
( %e di#erence 5.13 – 3.99 = 1.14 Example: Interpretation
If we take e (the base of the natural logarithms) to the
(5.13 – 3.99 =) 1.14 power, we "nd the ratio of the amount
of rainfall of the seeded clouds to the unseeded clouds
( exp(1.14) = 2.7182821.14 = 3.14
( Our best estimate is over three times as mu! rainfall
Unseeded: 3.99 (estimates the center of the unseeded
clouds on the log scale) Log Transformations
( log (ab) = log a + log b
log (a/b) = log a - log b
log (an) = n log a Log Transformations (cont.)
Log transformation on one group of data
( Positively skewed data
( Log transformation makes the distribution more symmetric
( %e mean and median are equal for symm...
View Full Document
This note was uploaded on 10/03/2011 for the course STAT 511 taught by Professor Eggett,d during the Winter '08 term at BYU.
- Winter '08