Interesting Card Trick Solution

Interesting Card Trick Solution - ranks of two turned cards...

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The Trick: The Trickster shuffles the deck and offers the Player a chance to shuffle. He then deals, face-up, five or six stacks. T turns the stacks over and then tells P to choose three. T then collects the remaining cards. T asks P to show the top cards on two of the stacks. T then tells the rank of the top card on the remaining stack. How did T do it? The Solution: T counted the remaining cards, N. Then he calculates N – (10 + sum of the
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Unformatted text preview: ranks of two turned cards). This is the rank of the top card on the remaining stack. The Algebra: Let x be the rank of the top card on the first chosen stack. Likewise, let y and z be the ranks of the top cards on the other two stacks. The number of cards in the first stack is 14-x and so for the other two. Thus, the number of remaining cards, N, is 52-(14-x)-(14-y)-(14-z) = 10+x+y+z=N. Hence T finds x = N-10-y-z....
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This note was uploaded on 10/05/2011 for the course ENGL 101 taught by Professor Smith during the Spring '10 term at Georgia Perimeter.

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