Unformatted text preview: ω t) as integrant and t as integration vari-able, press [Ctrl][.], click any place outside the box, we get, Z ke kt ± 80-10 cos( ωt ) ¶ dt = 80 e kt-10 k ± k k 2 + ω 2 e kt cos( ωt )+ ω k 2 + ω 2 e-kt sin( ωt ) ¶ So the solution is T ( t ) = e-kt ˆ 80 e kt-10 k ± k k 2 + ω 2 e kt cos( ωt )+ ω k 2 + ω 2 e kt sin( ωt ) ¶ + C !...
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This note was uploaded on 10/04/2011 for the course MAP 4231 taught by Professor Dr.han during the Spring '11 term at UNF.
- Spring '11