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Unformatted text preview: 2 , we have ( axbx 2 ) v + v x = axvbx 2 v + v x = abx + v x = 0 since xv = 1 So abx + v x = 0 (7) Divide (7) by x and notice 1 x is v , we have v + avb = 0 , or v + av = b. Apply the solution formula for linear equation we have v = eR adt Z be R adt dt + C ! So x = 1 v = e R adt R be R adt dt + C ! a Example 3.4 . In the logistic model, dx dt = axbx 2 , suppose a > ,b > are constants, we will discuss behavior of the solutions....
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This note was uploaded on 10/04/2011 for the course MAP 4231 taught by Professor Dr.han during the Spring '11 term at UNF.
 Spring '11
 Dr.Han

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