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Unformatted text preview: -between Exp 1 and Exp 2, and Exp 2 and Exp 4, [A] and [B] triples, rate triples-the order with respect to A and to B is 1 (both triple) k =0.010 1/Ms Example 16-3-first order A, first order B, second order overall-Exp 2: [A] = 0.80 M-Exp 3: [B] = 0.20 M-Integrated Rate Equation-1 st order ln [A] /[A] = a k t-d[A]/dt = a k t [A] = mol/L of A at time t=0 [A] = mol/L of A at time t k = specific T = 1/ak * ln([A] /[A])-half-life (t 1/2 ) of the reactant is the time required for half of the reactant to be consumed, or the time at which [A] = [A]-half-life is constant t = t 1/2 t 1/2 = 0.693/ ak ln [A] /[A] = a k t-use to find the time [A] = [A] e-akt Example 16-4 t/2 = 0.075 s Example 16-5 0.030 g Example 16-6 k = -0.00101 hr-1 [A] = 2.86 g left-2nd order 1/[A] 1/[A] = a k t t 1/2 = 1/ ak[A]-half-life depends on how much stuff was initially there Example 16-7...
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This note was uploaded on 10/04/2011 for the course CHEM 1212 taught by Professor Suggs during the Spring '08 term at University of Georgia Athens.
- Spring '08