2D Array For - #include #include void...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
#include <stdio.h> #include <string.h> void main() { float data2dArray[5][7]; //5 rows 7 cols /* row0-4=person 0-4 col0=rate col1=hours col2=gross col3=base col4=over col5=tax col6=net */ char nameArray[5][20]; //5 elements 19 char max for(int row=0;row<5;row++) { printf("Enter -1 to quit entering information\n"); printf("Enter name: "); gets(nameArray[row]); if (strncmp(nameArray[row],"-1",1)==0) //compare nameArray[row] to -1, by max 1 chars break; printf("Enter hourly rate: "); scanf("%f",&data2dArray[row][0]); if(data2dArray[row][0] == -1) break; printf("Enter hours worked: "); scanf("%f",&data2dArray[row][1]); if(data2dArray[row][1] == -1) break; printf("\n"); fflush(stdin); //calculate overtime and pay if(data2dArray[row][1]<40) //if hours worked less than 40 { data2dArray[row][4]=0; //overtime=0 data2dArray[row][3]=data2dArray[row][1]*data2dArray[row] [0]; //base pay=hours worked*hourly rate } else //if greater than 40 hours in a week { data2dArray[row][4]=(data2dArray[row] [0]*1.5)*(data2dArray[row][1]-40); //overtime=(rate*1.5)*(hours-40) data2dArray[row][3]=data2dArray[row][0]*40; //base pay=rate*40 }
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern