Lab Static Equilibrium IVC

Lab Static - Length 2 2 4 2 1 B A B M M LM y-= ΣF x = M A g cos φ – M A g cos φ = 0 T = M A g = M C g ΣF y = 2M A g sin φ – M B g = 0 A B

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Experiment 1 Static Equilibrium
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Draw Free body diagrams and equations of motion for static equilibrium set up.
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For Weights A and C ΣF x = 0 ΣF y = T - Mg Given M A = M C Then T = M A g = M C g Free Body Diagrams B M B g T B ΣF x = 0 ΣF y = T B - M B g
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Freebody diagram of Forces acting on washer is: M B g T T From Previous slide, given M A = M C , T = M A g = M C g
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½ L M B g φ ΣF x = T A cos φ – T C g cos φ = 0 For the washer, the sum of the forces, component-wise are: ΣF y = 2T sin φ – M B g = 0 (1) Therefore: sin φ = M B /2M A r (2) But trig tells us that y/r = M B /2M A (3) r = sqrt [(1/4)L 2 + y 2 ] y displacement as a function of Mass and
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Unformatted text preview: Length 2 2 4 2 1 B A B M M LM y-= ΣF x = M A g cos φ – M A g cos φ = 0 T = M A g = M C g ΣF y = 2M A g sin φ – M B g = 0 A B M M y L y 2 4 1 2 2 = + (4) (5) Begin your experiment for Static Equilibrium. Hold MB constant and change M A = M C for at least five weights to see if formula holds. Do a % error analysis and show the formula below is valid. At what weight M A does the system suddenly collapse? Show this mathematically. 2 2 4 2 1 B A B M M LM y-=...
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This note was uploaded on 10/05/2011 for the course PHYS 4A taught by Professor Ernest during the Summer '10 term at Irvine Valley College.

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Lab Static - Length 2 2 4 2 1 B A B M M LM y-= ΣF x = M A g cos φ – M A g cos φ = 0 T = M A g = M C g ΣF y = 2M A g sin φ – M B g = 0 A B

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