5.5 integrated problems

5.5 integrated problems - 5.5 Integrated Problems Trade...

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Unformatted text preview: 5.5 Integrated Problems Trade Discounts Discount D=dxL Net Price N=LD N = L(1 d) N = L (1 - d1) (1 - d2).....(1 dn) Discount Rate d=D/L Cash Discounts Amount Paid = Amount Credited x (1 d) Amount Credited = Amount Paid (1 d) Markup and Markdown M=E+P S=C+M S=C+E+P ROMC = M/C ROMS = M/S Sale Price = S(1 d) D=dxS Sale Price = S D pg. 216, #2: A gas barbecue cost a retailer $420 less 331/3%, 20%, 5%. It carries a regular selling price on its price tag at a markup of 60% of the regular selling price. During the end-of-season sale, the barbecue is marked down 45%. A) What is the end of season sale price? B) What rate of markup based on cost will be realized during the sale? Pg. 216, #4: An automatic dishwasher cost a dealer $620 less 37 %, 4%. It is regularly priced at $558. The dealer's overhead expense is 15% of the regular selling price and the dishwasher was cleared out at $432.45. a) What was the rate of markdown at which the dishwasher was sold? b) What is the regular markup based on selling price? c) What was the operating profit or loss? d) What rate of markup based on cost was realized? HOMEWORK: Ex. 5.5, pg. 216: A) 1, 3, 5 ...
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This note was uploaded on 10/04/2011 for the course MATH 1175 taught by Professor Jenny during the Spring '10 term at Fanshawe.

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5.5 integrated problems - 5.5 Integrated Problems Trade...

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