Notes_18_Entropy

Notes_18_Entropy - 1 This is going to seem pretty...

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Unformatted text preview: 1 This is going to seem pretty abstract..so Hang on for the ride! Meeting 17 Sections 7-17-6 What we covered Monday Carnot Corollaries Maximum (Carnot) Efficiency Absolute Temperature Scale Carnot Cycle Maximum (Carnot) COP 2 Topics for Today Clausius Inequality Entropy Generation Obtain Entropy Values Entropy Change Constant Entropy (___________) Processes Ts Diagram 3 4 Clausius Inequality Another corollary of the 2nd Law. Now we will deal with increments of heat and work, Q and W, rather than Q and W. We will employ the symbol , which means to integrate over all the parts of the cycle. 5 Look at a reversible power cycle Hot reservoir Cold reservoir System H Q L Q outR W 6 Look at a reversible cycle: 29 L H cycle Q Q Q- = We know: And: 29 W Q outR cycle = 7 For the reversible cycle cycle T Q - = L L H H T Q T Q Look at Q/T: Since the heat transfer occurs at ______________ temperature, we can pull T out of integrals: cycle T Q L L H H T Q T Q- = 8 For the reversible cycle H L rev H L T T Q Q = or L L H H T Q T Q = This allows us to write: cycle T Q T Q T Q H H H H =- = 9 For an irreversible cycle Hot reservoir Cold reservoir System H Q LI Q outI W 10 For an irreversible cycle outR outI W W < For the same heat input: For both cycles we can write: L H outR Q Q W- = LI H outI Q Q W- = and Apply inequality: L H LI H Q Q Q Q- <- or L LI Q Q- <- L LI Q Q or 11 Apply cyclic integral cycle T Q L LI H H T Q T Q- = T Q T Q L L H H =- < For the irreversible cycle: T Q cycle < 12...
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Notes_18_Entropy - 1 This is going to seem pretty...

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