This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Physics 315: Oscillations and Waves Homework 1: Solutions 1. The body will fly off the diaphragm whenever the diaphragms downward acceleration exceeds the acceleration, g , due to gravity. Hence, as the fre quency increases, the body will first fly off the diaphragm when the maxi mum downward acceleration becomes equal to g : i.e. , 2 a = g, Here, = 2 f is the diaphragms angular frequency of oscillation, f is the same frequency in hertz, and a is the amplitude of the oscillation. It follows that f = 1 2 radicalbigg g a . However, a = 1 10 5 m and g = 9 . 8 m s 1 , so f = 157 . 6 Hz. 2. Let x 1 and x 2 be the extensions of the first and second springs, respectively. The forces exerted by these springs are f 1 = k 1 x 1 and f 2 = k 2 x 2 , re spectively. If the springs are connected in parallel then x = x 1 = x 2 , where x is the downward displacement of the mass with respect to its equilibrium point. However, if the springs are connected in series then x = x 1 + x 2 . If the springs are connected in parallel then f = f 1 + f 2 , where f is the down ward force acting on the mass due to the springs. However, if the springs are connected in series then f = f 1 = f 2 . (N.B. f 1 equals f 2 because of Newtons third law of motion.) The generic equation of motion isNewtons third law of motion....
View
Full
Document
This note was uploaded on 10/04/2011 for the course PHY 315 taught by Professor Staff during the Spring '08 term at University of Texas at Austin.
 Spring '08
 Staff
 Acceleration, Gravity, Work

Click to edit the document details