me352_hw5_soln - 1 ME 352 System Dynamics and Control...

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Unformatted text preview: 1 ME 352 System Dynamics and Control Homework #5 – Solutions 1. (a) Type 0 (b) Type 1 (c) Type 3 (d) Type 0 2. Input Error Constants Steady-state Error ________________________________________________________________________________ u t s ( ) K K p = ) 1 ( 1 K + (a) tu t s ( ) K v = ∞ t u t s 2 2 ( ) / K a = ∞ The above results are valid if the value of K corresponds to a stable closed-loop system. ________________________________________________________________________________ u t s ( ) K p = ∞ 0 (b) tu t s ( ) 667 . 1 = v K 6 . t u t s 2 2 ( ) / K a = 0 ∞ ________________________________________________________________________________ (c) The closed-loop system is unstable. It is meaningless to conduct a steady-state error analysis. ________________________________________________________________________________ u t s ( ) 10 = p K 0.909 (d) tu t s ( ) = v K ∞ t u t s 2 2 ( ) / = a K ∞ 3. The following MATLAB code was used....
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This note was uploaded on 10/05/2011 for the course ME me352 taught by Professor Koraykadirsafak during the Spring '11 term at Yeditepe Üniversitesi.

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me352_hw5_soln - 1 ME 352 System Dynamics and Control...

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