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Unformatted text preview: 1 ME 352 System Dynamics and Control Homework #6 – Solutions s Solutions given for the following ID 2 5 0 7 0 5 0 0 5 6 5 5 5 = = ⇒ = = = b a z y x [1]. Unitstep response is obtained, on the sshaped response curve R and L values are calculated. Homework #6  PID Tuning Step Scope (s+a)(s+b) [1]*z_vec(s) Plant PID PID Controller cl Gain 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 0.01 0.02 0.03 0.04 0.05 0.06 time (s) y(t) ZieglerNichols Process Reaction Curve, R=0.0668, L=0.05 s. Optimal P, PI, and PID parameters are calculated and their closedloop responses are obtained. 2 0.5 1 1.5 2 2.5 3 3.5 4 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 time (s) y(t) Homework #6 Solution  PID Control, ZieglerNichols Process Reaction Method P Control, Kp=293.50 PI Control, Kp=264.15, Ki=1554.15 PID Control, Kp=352.20, Ki=3453.66, Kd=8.98 We observe that P control results in steadystate error. PI cancels the steadystate error but exhibits oscillations for some 45 cycles. PID yields faster decaying oscillations and no steadystate error. Among oscillations for some 45 cycles....
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This note was uploaded on 10/05/2011 for the course ME me352 taught by Professor Koraykadirsafak during the Spring '11 term at Yeditepe Üniversitesi.
 Spring '11
 koraykadirsafak

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