Exam1_Summer09_KEY - GENE 3200 Summer 2009 Bedell Exam 1...

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GENE 3200 – Summer 2009 – Bedell Exam 1 – June 17 ID no. 810_____ Corrected KEY 9/14/09 ________ Initials________________ 1 Write your ID number (810 number, NOT SSN) on every page . Write your initials on the first page only . All of the multiple choice questions have only one correct answer. The exam should be completed in ink. Regrades will not be given if you write in pencil. All requests to re-grade an exam must be made in writing to Dr. Bedell within 48 hours of the grades being posted on WebCT. ANSWERS TO NO. 1, 5, 6, 7, AND 30 HAVE BEEN CORRECTED SINCE 1 ST POSTING 1. (3 pts) What is Mendel’s first law? A. Dominant factors mask the expression of recessive factors B. Equal segregation C. Independent assortment D. Peas are the best experimental organism for genetics 2. (4 pts) Calculate the probability of the production of a homozygous recessive genotype for the following cross: AaBbccddEeFf × AaBbCcddEeFf This is like problem 16 of Ch 2 ¼ × ¼ × ½ × 1 × ¼ × ¼ = 1/512 3. (3 pts) In guinea pigs, rough coat (R) is dominant to smooth coat (r). A rough-coated guinea pig is bred to a smooth one, giving eight rough and seven smooth progeny in the F1. What are the genotypes of the parents and their offspring? Give a brief justification for your answer. Since rough is dominant to smooth, the ~ 1:1 segregation reveals that the parents are Rr (rough) and rr (smooth), the progeny are rr (smooth), and Rr (rough). 4. (3 pts) If one of the rough F1 animals from the previous question is mated to its rough parent, what progeny would you expect? Give a brief justification for your answer. F1 R/r X R/r -> 3:1 ratio of rough (R/-) and smooth (rr), 1:2:1 ratio of RR: Rr: rr 5. (3 pts) Albinism is a total lack of skin pigment due to a rare, autosomal recessive gene. You want to calculate the probability of a couple having an albino child. With this couple, both both are normally pigmented as are their parents, but both have albino siblings. Calculate the probability of a couple having an albino child. Show all equations needed to work this problem and give a brief justification for each answer. Ans: Since they both have albino siblings, their parents were carriers, therefore the probability of both of them being carriers is (2/3) 2 = 0.44, and the probability for their child to be affected is (2/3) 2 x 1/4 = 1/9 = 0.11. 6. (3 pts) For the pedigree to the right, what is the most likely mode of inheritance for the disorder. A. autosomal recessive B. autosomal dominant C. X-linked recessive D. X-linked dominant This is pedigree b in problem 29 of chapter 2
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GENE 3200 – Summer 2009 – Bedell Exam 1 – June 17 ID no. 810_______________________________ 2 6. In Drosophila, two autosomal genes are known to control wingsize and eye shape. For wingsize, t is the recessive allele for tiny wings and T is the dominant allele for normal wing size. For eye shape, n is the recessive allele for narrow eyes and N is the dominant allele for oval
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This note was uploaded on 10/05/2011 for the course GENE 3200 taught by Professor Condie during the Summer '08 term at University of Georgia Athens.

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Exam1_Summer09_KEY - GENE 3200 Summer 2009 Bedell Exam 1...

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