Thermo Answers f11

Thermo Answers f11 - Thermodynamics Homework Answers ME...

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Thermodynamics Homework Answers – ME 2124 – Fall 2011 Problem Answer(s) TD1 34.4 furlongs/fortnight TD2 4.21 × 10 8 yen/day 1.7 (a) 30.9 ft/s 2 ; (b) 150 lbf 1.16 - 25.8 ft/s 2 TD3 Explanation TD4 (a) open, fixed; (b) closed; (c) closed; (d) open, moving TD5 (a) T = 25 ° C = 25 K. Makes no difference (b) ° C: T 2 / T 1 = 1.833, K: T 2 / T 1 = 1.082. Makes a difference. TD6 33.3 kg 1.42 P 1 = 150 kPa = 1.48 atm, P 2 = 100 kPa = 0.99 atm TD7 (a) 28.0 kg/kgmol; (b) nitrogen, carbon monoxide, or ethylene TD8 (a) 0.00396 lbm; (b) 1275 ° F TD9 (a) 688 m 3 ; (b) 200 m 3 TD10 (a) Air 0.0739 lbm/ft 3 , Methane 0.0409 lbm/ft 3 , Propane 0.1125 lbm/ft 3 (b) Denser gas sinks 3.105 367 kPa gage TD11 (a) 7.80 ft 3 , 33,900 ft-lbf; (b) 1.00 ft 3 , 0; (c) Explanation TD12 (a) -1500 kJ; (b) 800 kJ; (c) 0; (d) -243 kJ 2.30 725 Btu 2.33 W 12 = 160.9 kJ, W 23 = 0, W 31 = -400 kJ 2.42 (a) W = – ( k /2)[( L 2 L 0 ) 2 – ( L 1 L 0 ) 2 ] (b) –20 J TD13 W 12 = 4,970 kJ, z 3 = -10.89 m TD14
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This note was uploaded on 10/05/2011 for the course ME 2124 taught by Professor Uzgoren during the Spring '08 term at Virginia Tech.

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Thermo Answers f11 - Thermodynamics Homework Answers ME...

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