Unit18 Group16 - Chalcogens qns

Unit18 Group16 - Chalcogens qns - 1 Unit 18 Group 16 or VIA...

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1 QUEST TUTORIALS Head Office : E-16/289, Sector-8, Rohini, New Delhi, Ph. 65395439 Unit 18 Group 16 or VIA group (Chalcogens) 1. The outer shell configuration of Se is (a) 2s 2 2p 4 (b) 3s 2 3p 4 (c) 4s 2 4p 4 (d) 5s 2 5p 4 2. Though second EA of oxygen is endothermic O (g) + e O (g) Δ H = –ve O (g) + e O 2– (g) Δ H = +ve Oxides are formed predominantly due to (a) high E.N. of oxygen (b) high I.E. of oxygen (c) high E.N. of oxygen (d) high Δ H lattice of oxides 3. The tendency to form divalent anions decreases from oxygen to Po as (a) size of atom increases (b) E.N. decreases (c) I.E. decreases (d) all the above 4. The sulphur has greatest capacity for catenation is evident from the formation of (a) dichloro sulphanes, SxCl 2 ( x may be 100 ) (b) poly sulfides, Sx 2– (x = 6 ) (c) poly sulphonic acids (d) all the above 5. Of the hydrides, H 2 O, H 2 S, H 2 Se, H 2 Te, the one which with the largest bond angle is (a) H 2 O (b) H 2 S (c) H 2 Se (d) H 2 Fe 6. Refer to Q4, which has smallest pKa value ? (a) H 2 O (b) H 2 S (c) H 2 Se (d) H 2 Te 7. Refer to Q4, which one exists as an associated liquid? (a) H 2 O (b) H 2 S (c) H 2 Se (d) H 2 Te 8. Reducing power of hydrides decreases from H 2 O to H 2 Te as (a) size of the electro-negative ion increases from O 2– to Po 2– (b) stability of the hydrides decreases (c) as bond angle decreases (d) all the above 9. SF 6 has which geometry and mode of hybridizations? (a) Sp 3 d 2 , Octahedral (b) Sp 3 d, pyramidal (c) Sp 3 d 2 , square planar (d) none of these 10. SF 4 has a geometry (a) octahedral (b) trigonal bipyramidal (c) square planer (d) angular 11. Which of the following hybridisation and geometry of the molecules is wrongly matched? (a) SO 2 , Sp 2 , bent (b) SO 3 , triangular planer, Sp 2 (c) SO 4 2– , Sp 3 , tetrahedral (d) SeO 2 , Sp 2 , angular 12. SO 3 is iso-electronic in its valency shell with (a) BF 3 (b) NO 3 (c) CO 3 2– (d) all the above 13. The equivalency of all the S – O bonds in SO 3 is accounted for by: (a) the octet rule (b) resonance involving p π – p π (c) electron – pair repulsion theory (d) knowing that S forms 3 equivalent bonds 14. Oxygen shows oxidation states of (a) –2 (b) –1 (c) –1/2 (d) all of the above 15. Sulphurous acid, H 2 SO 3 has (a) symmetrical structure (b) unsymmetrical structure (c) both (d) none of all 16, The high viscosity and B.P. of H 2 SO 4 is (a) reflected in its structure (b) due to its capacity to form H–bonds (c) due to polarizing ability of SO 4 2– ion (d) none of these
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2 QUEST TUTORIALS Head Office : E-16/289, Sector-8, Rohini, New Delhi, Ph. 65395439 17. H 2 SO 4 is used to displace strong acids such as HCIO 4 , HNO 3 , HCI from their salts because of its (a) high viscosity (b) high dielectric constant (c) high b.p (d) high solubility in water 18. The oxidation state of S in permonosulphuric acid H 2 SO 5 , (caro’s acid) and per di-sulphuric acid, H 2 S 2 O 8 (Marshell’s acid) is (a) +2
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This note was uploaded on 10/05/2011 for the course CHEM 1201 taught by Professor Darcy during the Spring '11 term at St. Mary NE.

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Unit18 Group16 - Chalcogens qns - 1 Unit 18 Group 16 or VIA...

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