problem02_04solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.4: The eastward run takes ) s m 5.0 m 200 ( = 40.0 s and the westward run takes ) s m 4.0 m 280 ( = 70.0 s. a) (200 m + 280 m)/(40.0 s + 70.0 s) = s m 4 . 4 to two significant figures. b) The net displacement is 80 m west, so the average velocity is
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Unformatted text preview: ) s 110.0 m 80 ( = s m 73 . in the – x-direction ). ˆ ( i-...
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This document was uploaded on 02/04/2008.

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