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Pre-Calc Homework Solutions 231

# Pre-Calc Homework Solutions 231 - Chapter 5 Review 1 x 1 x2...

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49. y 9 5 2 x 1 } 1 x } y 0 5 2 2 } x 1 2 } Thus, it satisfies condition i. y (1) 5 1 1 E 1 1 } 1 t } dt 1 1 5 1 1 0 1 1 5 2 y 9 (1) 5 2 1 } 1 1 } 5 2 1 1 5 3 Thus, it satisfies condition ii. 50. Graph (b). y 5 E x 1 2 t dt 1 4 5 3 t 2 4 1 4 5 ( x 2 2 1) 1 4 5 x 2 1 3 51. (a) Each interval is 5 min 5 } 1 1 2 } h. } 2 1 4 } [2.5 1 2(2.4) 1 2(2.3) 1 1 2(2.4) 1 2.3] 5 } 2 1 9 2 } < 2.42 gal (b) (60 mi/h) 1 } 1 2 2 9 } h/gal 2 < 24.83 mi/gal 52. (a) Using the freefall equation s 5 } 1 2 } gt 2 from Section 3.4, the distance A falls in 4 seconds is } 1 2 } (32)(4 2 ) 5 256 ft. When her parachute opens, her altitude is 6400 2 256 5 6144 ft. (b) The distance B falls in 13 seconds is } 1 2 } (32)(13 2 ) 5 2704 ft. When her parachute opens, her altitude is 7000 2 2704 5 4296 ft. (c) Let t represent the number of seconds after A jumps. For t \$ 4 sec, A’s position is given by S A ( t ) 5 6144 2 16( t 2 4) 5 6208 2 16 t , so A lands at t 5 } 62 1 0 6 8 } 5 388 sec. For t \$ 45 1 13 5 58 sec, B’s position is given by S B ( t ) 5 4296 2 16( t 2 58) 5 5224 2 16 t , so B lands at t 5 } 52 1 2 6 4 } 5 326.5 sec. B lands first.
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