Pre-Calc Homework Solutions 234

Pre-Calc Homework Solutions 234 - 234 Section 6.1 dy dx dy...

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Unformatted text preview: 234 Section 6.1 dy dx dy dx dx 24. cot 2 t dt 25. (a) Graph (b) (csc 2 t 1) dt cot t t C 29. sec 2 x sec 2 x dx tan x C 4 (b) The slope is always positive, so (a) and (c) can be ruled out. 26. (a) Graph (b) (b) The solution should have positive slope when x is negative, zero slope when x is zero and negative slope when x is positive since slope dy dx y Initial condition: y 1 1 2 tan 1 C tan x 4 1 C C x. Graphs (a) and (c) don't show this slope pattern. 27. dy dx dy dx dx Solution: y 2 2x (2x x2 1 1) dx x C 0 30. 2 2 2 dy dx dy dx dx y Initial condition: y(2) 0 22 2 C 0 2 C 2 C Solution: y x 2 x , by [ 8, 8] x x 2/3 2/3 dx C 5 C y 3x 1/3 [ 4, 4] by [ 3, 3] Initial condition: y( 1) 5 3( 1)1/3 5 3 C 2 C y 3x 1/3 2 28. dy dx dy dx dx 1 x2 x 2 1 (x x x2 2 2 2 3 2 2 x) dx x2 2 y y C [ 4, 4] by [ 8, 4] 1 x 1 2 C 1 C 31. Initial condition: y(2) 1 1 1 2 dy dx dy dx dx 9x 2 (9x 2 3x 3 4x 4x 2x 2 5 5) dx 5x C C y 1 x 1 2 C x2 2 Solution: y Initial condition: y( 1) 0 0 3( 1)3 2( 1)2 5( 1) C 0 10 C 10 C Solution: y 3x 3 2x 2 5x 10 [ 6, 6] by [ 4, 4] ...
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This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.

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