Unformatted text preview: 8 C. 35. (a) } d d T t } 5 2 k ( T 2 T s ) } T 2 dT T s }5 2 k dt E } T 2 dT T s }5 2 k dt ln ) T 2 T s ) 5 2 kt 1 C ) T 2 T s ) 5 e 2 kt 1 C T 2 T s 5 6 e C e 2 kt T 2 T s 5 Ae 2 kt Initial condition: T 5 T when t 5 T 2 T s 5 Ae 2 ( k )(0) T 2 T s 5 A Solution: T 2 T s 5 ( T 2 T s ) e 2 kt (b) lim t → ‘ T 5 lim t → ‘ [ T s 1 ( T 2 T s ) e 2 kt ] 5 T s Horizontal asymptote: T 5 T s 36. (a) 2 y 5 y e rt 2 5 e rt ln 2 5 rt t 5 } ln r 2 } (b) [0, 0.1] by [0, 100] (c) ln 2 < 0.69, so the doubling time is } 0. r 69 } which is almost the same as the rules. (d) } 7 5 } 5 14 years or } 7 5 2 } = 14.4 years Section 6.4 263...
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 Spring '08
 GERMAN
 Trigraph, TS, lim T, ts ts ts, kt C

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