Pre-Calc Homework Solutions 359

Pre calc homework solutions 359

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Unformatted text preview: Chapter 8 Review 46. u du x dx 1 x 3 1 x 3 359 dv v e3x e 3x e 3x dx 1 3x e 3 1 3x e dx 3 Note that the integral must be broken up since the integrand has infinite discontinuities at t 0 1 0 and t 1. x e3x dx 1 3x e 9 0 C dx 1 3x e 9 1 3b be 3 C t 1 0 b 4t 3 t 1 dt t 2(t 1)(t 2 1) b 1 0 xe 3x dx lim b b xe 3x lim b0 4t 3 t 1 dt t (t 1)(t 2 1) 2 lim b 1 3x xe 3 1 9 A t B t2 lim b0 1 t 1 b ln (t 1)2 t2 1 b tan tan 1 t 1 lim b 1 3b e 9 Dt t2 E 1 1 9 lim b0 (b 1)2 ln 2 b 1 4 1 b 4t 3 t 1 47. 2 t (t 1)(t 2 1) 1 ln 2 Since this...
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