Pre-Calc Homework Solutions 360

Pre-Calc Homework Solutions 360

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: hat we cannot use a comparison test since e x cos x 0 for some values on [0, ). 1 51. 0 z dz z e ln z on [e, ) z b dz b lim lim ln z lim (ln b 1) e b b e z b 1 dz diverges, so the given Since this integral diverges, e z dx x (1 e x ) 2 1 0 1 dx x 2(1 e x ) dx x 2(1 e x ) 0 dx x 2(1 e x ) 1 0 1 0 1 4x 2 dx 4x 2 1 x 2(1 1 ex ) dx 4x 2 on (0, 1] since 1 lim b0 1 ex lim b0 4 on (0, 1]. 1 4 1 4b lim b0 b 1 1 4x b 0 integral diverges. e t t Since this integral diverges, given integral diverges. dx diverges, so the x 2(1 e x ) 52. 0 e 1 e t t o...
View Full Document

This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online