Pre-Calc Homework Solutions 405

Pre-Calc Homework Solutions 405 - Section 10.2 dy dx 3 0...

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40. } d d y x } 5 e x , so Area 5 E 3 0 2 p e x ˇ 1 w 1 w ( w e w x ) w 2 w dx which using NINT evaluates to < 1273.371. 41. } d d y x } 5 2 } x 1 2 } , so Area 5 E 4 1 2 p 1 } 1 x } 2 ! 1 § 1 § 1 § 2 § } x 1 § 2 } 2 § 2 § dx , which, using NINT, evaluates to < 9.417. 42. } d d y x } 5 (ln 2)2 x 2 (ln 2)2 2 x 5 (ln 2)(2 x 2 2 2 x ), so Area 5 E 2 2 2 2 p (2 x 1 2 2 x ) ˇ 1 w 1 w ( w ln w 2 w ) 2 w (2 w x w 2 w 2 w 2 w x ) w 2 w dx which using NINT evaluates to < 116.687. Section 10.2 Vectors in the Plane (pp. 520–529) Quick Review 10.2 1. ˇ (5 w 2 w 1 w ) 2 w 1 w ( w 3 w 2 w 2 w ) 2 w 5 ˇ 1 w 7 w 2. } 3 5 2 2 2 1 } 5 } 1 4 } 3. Solve } 3 5 2 2 b 3 } 5 2 4: b 5 11. 4. Slope of A w B w = Slope of C w D w , so } 3 1 2 2 0 0 } 5 } 3 5 2 2 0 a } and a 5 4. 5. Slope of A w B w = Slope of C w D w , so } 5 3 2 2 1 1 } 5 } 2 6 2 2 b 8 } 5 and b 5 6. 6. (a) u 5 120 8 (b) u 5 } 2 3 p } 7. (a) u 5 2 30 8 (b) u 5 2 } p 6 } 8. (a) u 5 2 45 8 (b) u 5 2 } p 4 } 9. c 2 5 3 2 1 5 2 2 2(3)(5) cos (30 8 ) 5 34 2 15 ˇ 3 w , so c 5 ˇ 3 w 4 w 2 w 1 w 5 w ˇ w 3 w w < 2.832 10. 24 2 5 27 2 1 19 2 2 2(27)(19) cos u , so cos u 5 5 } 2 5 5 1 7 3 } and u 5 cos 2 1 } 2 5 5 1 7 3 } < 1.046 radians or 59.935 8 .
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