Pre-Calc Homework Solutions 447

Pre calc homework solutions 447

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Unformatted text preview: Cumulative Review 68. Let t be the time in minutes where t 0 represents right 72. The region has four congruent portions, so /2 447 now, and let T(t) be the number of degrees above room temperature. Then we may write T(t) T(0) k 50 and T( 15) 13 1 ln 10 15 k(120) Area 73. Solve 5 2x 2 Area 4 0 sin 2x dx x2 x2 4 1 cos 2x 2 /2 4 0 T0e kt where 3 to find the integration limits: 65, giving T0 50 and 8x 2 2. Then x 2) 64 3 0.0175. 6.13C above room temperature. 50e kt [(5 2 (x 2 2 3)] dx (8 2 2x 2) dx (a) 50e 8x 74. Solve y y2 y 2 (b) Solving 5 gives t ln 0.1 k 2 3 x 3 2 2 131.6 minutes, 3 5 (1 (1 2 0 or about 2 hours and 12 minutes from now. dy y 0.08y 1 dx 500 500 dy 0.08 dx y(500 y) (500 y) y dy 0.08 dx y(500 y) 1 1 dy 0.08 dx y 500 y y 0y 21)/2 2 to find the integration limits: 1 2 21 . Then 3) dy 16.039. 69. Area 21)/2 [(y 1 2 2 0 2 0 2 0 2) 1 2 2 0 (y 2 75. Area 9 2 9 2 r2 d 2 cos 2 cos cos 9(1 cos )2 d (1 1 3 2 cos2 ) d 1 cos 2 2 Integrate both sides. ln y y 500 y d ln 500 y 0.08x C1 9 2 1 cos 2 2...
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This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.

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