Pre-Calc Homework Solutions 472

Note that gk t m ln 81 2 sinh ln 81 2 ln 16 2 g sech2

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Unformatted text preview: m mg tanh k 2 gk t m ln 16 4 [ln (81 16) 4 [ln (9 4)2 4 4 4 2 ln 36 4 ln 6 4 ln 6 9 80 9 320 2 sinh mg sech2 mg mg 1 k 2 sinh (ln 9) (e ln9 1 9 15 4 135 36 2 sinh (ln 4)] (e ln 4 e ln 4 mg kv 2 e ln 9 ) 1 4 )] tanh2 2 gk t m 4 mg sech2 Thus, m dv and mg dt gk t. m kv 2 are equal to the same quantity, so 16 ln 6 455 9 248.889 the differential equation is satisfied. Furthermore, the initial condition is satisfied because v(0) mg tanh 0 k 0....
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This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.

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