Pre-Calc Homework Solutions 472

Pre calc homework solutions 472

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Unformatted text preview: 472 Appendix A6 1 cosh 2x y 2 ln 0 5 64. (a) y sinh 2x L ln 5 0 68. (a) s(t) cosh 2x dx ds dt d 2s 2 dt a cos kt b sin kt bk cos kt bk 2 sin kt k 2 s(t) acceleration is k 2 implies 1 (sinh 2x)2 dx ak sin kt ak 2 cos kt 1 ln 5 sinh 2x 2 0 1 1 6 5 4 5 5 1 (b) y cosh ax 1 a b 1 e 2x e 2 2 2x ln 5 0 k 2(a cos kt cosh2 ax sin kt) proportional to s. The negative constant (y )2 b 0 1 sinh2 ax L 0 cosh2 ax dx sinh ab a f ( x) that the acceleration is directed toward the origin. (b) s(t) a cosh kt ak sinh...
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