Pre-Calc Homework Solutions 472

B st a cosh kt ak sinh kt ak 2 cosh kt b sinh kt bk

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Unformatted text preview: kt ak 2 cosh kt b sinh kt bk cosh kt bk 2 sinh kt k 2 s(t) acceleration is cosh ax dx sinh ax b a 0 65. (a) Let E(x) f ( x) . Then 2 2 f (x) f ( x) f (x) f ( x) 2 f (x) E(x) O(x) 2 2 2 f ( x) f ( ( x)) f (x) f ( x) f (x). Also, E( x) 2 2 f ( x) f ( ( x)) E(x) E(x) is even, and O( x) 2 f (x) f ( x) O(x) O(x) is odd. 2 f (x) and O(x) f (x) ds dt d 2s 2 dt k 2 (a cosh kt sinh kt) proportional to s. The positive constant k 2 implies that the acceleration is directed away from the origin. dy dx 1 x 1 x x 1 1 1 2 Consequently, f (x)...
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This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.

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