9 - -M = 1 gram = 0.001 kg-C^2 = 9x10^16 m2/s2) E = (0.001...

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- When hydrogen fuses into Helium, matter disappears and turns into energy. - 0.7% of the Hydrogen mass disappears - Question: if 1 gram of matter disappears, how many joules of energy will be produced. - 1 joule = kgm^2/m^2 . (eg: a 100 watt light emits 100 joules per second) - In nuclear reactions, mass is converted into energy E=mc^2 - M is the mass lost (not the total mass), in Kilograms (kg) - E is the energy produced, in Joules (J)
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Unformatted text preview: -M = 1 gram = 0.001 kg-C^2 = 9x10^16 m2/s2) E = (0.001 kg) x (9x 10^16 m2/s2) E = 9x10^13 kg m2/s2 = 9x10^13 Joules of energy This is equal to the energy released by 25,000 tons of dynamite exploding! (25 Kilotons of TNT) Also, its equal to the energy in 1 million gallons of gasoline! All from 1 gram of mass disappearing! Nuclear Fusion in the Sun...
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