Physics 102 Notes

Physics 102 Notes - OM - PR EME D41 1.C P FORM 0 1.C OM...

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Unformatted text preview: OM - PR EME D41 1.C P FORM 0 1.C OM Physics 102 [C] 9.07T x 109 N D41 [B] 9.0 x 109 N &&%* x 109 N - PR EME [A] 4.0 x 109 N [E] 367T x 109 N 1.C OM - PR EME D41 [l] A p erfectly conducting hollow sphere of radius 1.0 meter is centered at the origin and has a surface charge density of 1.0 C /m 2 . What is the magnitude of the force that a 1.0 C test charge will feel if it is located at a position x — 1.0 m, y — 1.0 m, z = 0.0 m (thus on the x-y plane)? ^ 1.C OM [2] For the conducting sphere in the above problem, what is the magnitude of the electric field at the origin and on the surface? - PR EME D4 11. COM - PR EME D41 [A] 0 N /C, 0 N /C [B] 0 N /C, 2.07rfc N /C N/C, 4.07rjfc N /C 2.071-A; N /C, 2 .07rfc N /C [E] 4.07T& N /C, 4.071-fc N/C COM [3] If a negative point charge of —4.07T Coulombs is placed at the center of the hollow, conducting sphere described above, what is the electric flux t hrough a sphere with a radius .O meters, centered at the origin? O.ONm 2 /C [ B] -2.07rJfe N m 2 /C [ C] 2.07rfc N m 2 /C [ D] - 4.07rfc N m 2 /C 2 4.07rfc N m /C - PR EME D4 11. f [E] F " COM - PR EM ED4 11. COM [4] A charge -\-q is fixed at the origin. A charge — q has a mass m and s tarts at rest at an initial distance r^ from the origin. What is the speed of the —q charge when its distance from the origin becomes r ^? ( Assume TB < [A] 0 [B] 11. • TA - PR EM ED4 11. COM - PR EM ED4 [5] Circuit A contains two capacitors in series. Circuit B contains 2 capacitors in parallel. All capacitors in b oth circuits have capacitance C. In which circuit would a dielectric material need to be added in order to make the equivalent capacitances of circuits A and B be the same, and w hat would the dielectric constant of the material need to be? [A] circuit A, 2 ([Sh circuit A, 4 [C] circuit B, 1/2 [D] circuit B, 2 [E] circuit B, 4 11. COM - PR EM ED4 11. COM [6] A parallel-plate capacitor is connected to a b attery and maintained at a constant potential V. It is initially filled by vacuum and it has plates with area A separated by a distance d. If A is increased by 2, d is decreased by 2 and a dielectric with K — 2 is inserted between the plates, how much does the stored energy change? |A] 0 [B] decreases by 2 [C] increases by 2 [D] decreases by 8 flE|)increases by 8 PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 [7] The resistivity of the material of a wire is 1.76 X 10~8 fi-m. If the radius of the wire is 2.0 mm and its length is 2.0 m, what is its resistance? (JAJ/0.0028 0 [B] 0.011 ft [C] 0.51 0 [D] 2.5 ft [E] 37 0 OM - PR EME D41 1.C P FORM 0 1.C OM Physics 102 OM - PR EME D41 1.C OM - PR EME D41 [8] An RC circuit is connected across a DC voltage source through an open switch. The switch is closed at i = 0 s. Which of the following is a correct statement regarding this circuit? [A] The capacitor charges to its maximum value in two time constants. [B] The resistor and the capacitor share the applied voltage equally as a f unction of time. [C] The current flows t hrough the circuit even after the capacitor is fully charged. [D] The time constant does not depend on the resistance or the capacitance. (jEJjOnce the capacitor is fully charged, there is no current in the circuit. - PR EME D41 1.C [9] A square coil, 5.0 cm on a side, has 250 t urns. When the coil is placed in a magnetic field of 0.40 T, its maximum t orque is measured to be 0.25 N -m. The current in the coil is [A] 0.010 A [B] 0.125 A (fC])l.O A [D] 2.5 A [E] impossible to determine 11. COM - PR EME D4 11. COM [10] Two long parallel wires carry currents of 4.00 A and 5.00 A, respectively. If the distance between the wires is 40.0 cm, w hat is the force per unit length between the wires? [A]7.50^N/m (JMIO.O/tN/m [C] 1 5.0/xN/m [D] 20.0 [E] 30.0 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EME D4 [13] When a charged particle enters a region of a uniform magnetic field B, directed into the plane of motion, it follows a circular path, as indicated in the figure. (a) Is this particle positively or negatively charged? Explain. (b) Suppose t hat the magnetic field has a m agnitude of 0.200 T, the particle's speed is 5.07 X 105 m /s, and the radius of the p ath is 50.0 cm. Find the mass of the particle, given that its charge has a magnitude of 1.60 x 10~19 C. Give your results in atomic mass units, where 1 u = 1.66 X 10~27 kg. - COM - PR EM ED4 Cb) PRE MED 411 .CO MPRE M ED4 11. ff\ - <8>B (g) OM - PR EME D41 1.C P FORM 0 D41 1.C OM Physics 102 A) COM - PR EME D4 11. COM - PR EME D41 1.C OM - PR EME D41 1.C OM - PR EME [11] An electron is fixed at x = — 1.00 mm and a p roton is fixed at x = +1.00 mm. G ive numerical results when possible. Make sure to provide the m agnitude and direction for vector quantities. Provide the u nits of the answer. (a) What is the p otential energy of this configuration? (b) What is the electric potential at the origin (thus at x = 0 )? (c) W hat is the magnitude and direction of the electric field at the origin? (d) Assume t hat an additional proton is put at the origin, and find the m agnitude and direction of the electric force on it. - PR EM ED4 11. COM - PR EME D4 11. U- PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM -Ue ov \ OM - PR EME D41 1.C P 1.C OM Physics 102 - PR EME D4 11. COM - PR EME D41 1.C OM - PR EME D41 1.C OM - PR EME D41 [12] The figure shows a circuit including a b attery of emf B = 24 V and internal resistance T - 0.50 ft, and five resistors: J?a = 2.5 ft, R2 = 5.0 ft, R3 = 8.0 ft, R± = 6.0 ft, R5 = 2.0 ft. (a) Find the t otal resistance of the circuit, and the current flowing through the b attery. (b) Find the currents flowing through the resistors #3 and R$. (c) Calculate the power dissipated by the resistor R5. (d) Suppose point B is grounded (VB = 0). Find the potential at points A and C. PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EME D4 11. COM u,o OM - PR EME D41 1.C P FORM 0 1.C OM Physics 102 D41 1.C OM - PR EME D41 FORMULAE SHEET me = 9.11 x I0~3lkg, - PR EME e = 1.60 x 10~19C, IkWh = 3.6 x 106 J, e0 = ^- - 8.85 x lQ-12C*/Nr D41 1.C OM = 1-60 X 10"19 J, k = 8.99 x W»Nm?/C2 COM - PR EME E = —, |£| = A;-!-, *E = So r2 " V0 y " Ke0A = " ' ' —> CV2 QV UB= Q2 = ^ " ' e0E* ^ = ~~' r Aq J =r > /- e xp(-i/r), sin6, g = Q exp ( -f/r), r = NIABsin6, 1= r n0 = 4?r x 1(T7—— PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EME D4 11. COM ' - PR EME D4 Q V= A F = -EAs, 7, 11. qo (long)' 27nf (coil) ' (solenoid) ...
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