Physics 102 Notes a

Physics 102 Notes a - OM - PR EME D41 1.C P Physics 102...

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Unformatted text preview: OM - PR EME D41 1.C P Physics 102 FORM 0 - PR EME D41 1.C OM - PR EME D41 1.C OM [l] The area of a rectangular loop of wire is 6.4 x 10~3 m 2 . The loop is placed in a magnetic field t hat changes from 0.20 T to 1.2 T in 1.6 s. The plane of the loop is perpendicular to the direction of the magnetic field. W hat is the magnitude of the i nduced emf in t hat loop? ^-, 3 [A] 2.1 x 10~ V f[B]J4.0 x 10~3 V [C] 6.7 x 10~3 V [D] 8.4 x 10"3 V 3 [E] 9.8 x I D" V ^ - PR EME D41 1.C OM [2] A circular coil with 600 t urns has a radius of 15 cm. The coil is rotating about an axis perpendicular to a magnetic field of 0.020 T. If the maximum induced emf in the coil is 1.6 V, at what angular speed is the coil rotating? [A] 0.30 r ad/s [B] 0.60 r ad/s [C] 0.90 r ad/s [D] 1.4 r ad/s ([E])l.9 rad/s - PR EME D4 11. COM [3] A 25-mH i nductor is connected in series with a 20-0 resistor, through a 15-V DC power supply and a switch. If the switch is closed at t = 0 s, w hat is the current after 0.70 s? [A] 120 mA [B] 280 mA [C] 450 mA [D] 570 mA (®)750 mA - PR EME D4 11. COM [4] According to the little metal plate on a hair dryer, it is r ated at 120 Vrms and an average power of 1500 W. Assuming the load to be purely resistive, what is the maximum value of current in the dryer? _^ [A] 12.5 A [B] 14.1 A (fcj)l7.7 A [D] 25.0 A [E] 35.3 A COM [5] An electromagnetic wave is propagating towards the west. At a certain moment the direction of the magnetic field vector associated with the wave points vertically up. What ''ie direction of trhe electric-field v ector? [B] Vertical and p ointing down Horizontal and pointing south [D] Vertical and pointing up Horizontal and pointing north [E] Horizontal and pointing east COM - PR EM ED4 11. f COM - PR EM ED4 11. [6] An 8.00-mW (average power) laser beam emits a cylindrical beam of light, 0.900 mm in diameter. What is the rms value of the electric field in t his beam? _ [A] 412 N/C [B] 1000 N/C [C] 1090 N/C [D] 2000 N/C ([Ej) 2180 N/C - PR EM ED4 11. [7] A convex mirror has a radius of curvature of R = 1 meter. An object is placed at a distance of(3.5 meters in front of the mirror. What is the image distance? (JA])-0.25 m [B] 0.25 m [C] -0.5 m [D] 0.5 m [E] 1 m 11. COM - PR EM ED4 11. COM [8] An optical device produces an upright virtual image t hat is reduced in size. What could this optical device be? [A] convex mirror or convex lens {LBJjconvex mirror or concave lens [0] concave mirror or convex lens [D] concave mirror or concave lens [E] plane mirror PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 [9] A convex lens forms a real, enlarged image. If the object distance is 2.0 meters and the image distance is 3-0 meters, what is the focal length and the magnification? [A] -1.2 meters, -1.5 [B] -1.2 meters, 1.5 | jCj>1.2 meters, -1.5 [D] 1.2 meters, 1.5 [E] none of these OM - PR EME D41 1.C P Physics 102 FORM 0 - PR EME D41 1.C OM - PR EME D41 1.C OM [10] A nearsighted person has a far point t hat is 52 cm from her eye. What diopter lens will correct this person's vision so that she can focus on distant objects? Assume the lens is placed 2 cm in front of her eye. [A] -0.02 [B] -0.5 [C] 0.5 (j]DJ)-2 [E] 2 - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EME D4 11. COM - PR EME D4 11. COM - PR EME D41 1.C OM [ll] The p icture below shows a zero-resistance rod of mass m = 0.10 kg sliding, due to gravity, downward on two zero-resistance rails separated by the distance L = 0.20 m. The rails are connected by a resistor R = 0.10 f i, and the entire system is in a perpendicular uniform magnetic field with a magnitude B = 0.50 T, pointing out of the plane. Assume t hat the velocity v of the rod has reached an equilibrium constant value, and find (taking g — 10 m /s 2 , and ignoring the effect of air resistance) (a) the magnitude and direction of the magnetic force acting on the rod under such an equilibrium; (b) the magnitude and direction (clockwise or counterclockwise) of the induced current in the circuit; (c) the magnitude of the induced emf in the circuit; (d) the equilibrium speed v of the rod. ••> s vvvv ' V""1 f/ ^ © © v ©I ,^,^«^, «4*, «-^ m © v © x, ® © \ ©©© © w wm e COM T 11. COM - PR EM ED4 11. © 0 0/K. © © - io-o.lt>V= U >IA - PR EM ED4 11. COM - PR EM ED4 tx PRE MED 411 .CO MPRE M ED4 11. COM 7 r ~ -b__ 6L ui, OM - PR EME D41 1.C P FORM 1 OM Physics 102 D41 1.C OM - PR EME D41 1.C [12] An uupolarized light source with an i ntensity I0 is incident on a polarizer A. (a) Find the relative orientation of a second polarizer (polarizer B) such that the t ransmitted intensity through it is Jo/10. (b) Find the relative orientation of a t hird polarizer (polarizer C) w ith respect to polarizer A such t hat no light is t ransmitted through polarizer C. Assume t hat polarizer B is between polarizers A and C. TD (S - PR EME D4 11. COM Tit) so To TVV1- JO Co<MLtC\ - PR EME D4 11. COM - PR EME D41 1.C OM - PR EME (c) Now you are challenged to maximize the t ransmitted intensity of all three polarizers by rotating polarizer B to some angle Q with respect to polarizer A. Using the results from above, write down an expression for the total transmitted intensity through polarizer C in terms of this 9. You don't have to solve for the d t hat m aximizes the intensity. TD ED4 11. COM - PR EM ED4 11. COM A ls, _ PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM - C— S -O =^> OM - PR EME D41 1.C P OM Physics 102 PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EM ED4 11. COM - PR EME D4 11. COM - PR EME D4 11. COM - PR EME D41 1.C OM - PR EME D41 1.C OM - PR EME D41 1.C [13] A ray of light travels through air (index of refraction n i) and strikes a plane mirror that has a glass coating with an index of r efraction n^ > ni and a thickness t. The angle of incidence is 6 and it strikes the glass at a height h above the ground. The ray is subsequently refracted, reflected and refracted before it hits the ground a distance d away from the mirror. Find the distance d in terms of the above parameters. Steps: (1) Find the angle of refraction as the ray penetrates the glass. (2) Find the angle of reflection from, the mirror. (3) Find the angle of refraction as the ray leaves the glass. (4) Use trigonometry to find d. 6 b 0\\ OM - PR EME D41 1.C P Physics 102 F ORM 0 - PR EME D41 1.C OM FORMULAE SHEET me = 9.11 x 1(T31%, k = 8.99 X l09Nm2/C2 1.C OM e = 1.60 x lO"19^ IkWh = 3.6 x 106 J. e0 = — = 8.85 x !Q-i:iC*/Nm? D41 leV = 1.60 x 10~19J, OM - PR EME 4:TTK 1.C €Q Wnc = AJT + AZ7, COM 2 2 - PR EME D4 11. ' WE 2 C' COM 11. - PR EME D4 Ai i 2 .. q = Q^p(-t/r), COM T //0 = 4?r x 10~7 ED4 11. T =~NIAB sinQ, N/J.Q! r> - ~ 2^"' £ = vBl. (coil) £ = NABu> sino^i, ' . rN -- (solenoid) u — 2-n-f = — T ~R COM T= - PR EM ED4 11. = ~ tt J=l A - PR EM COM 11. :——, At r- ' - PR EM ED4 £= V= . .., J=|«p(-f/T)J (long)' ?, ^ -nlCo ..., - = - TV K = -"' -T*R = -5-. ^ = ^ p= ^0 AT^ = -EAs, - PR EME = - g 0 AV, go ^ ^Q D41 UB k = -^-, E — cB, c= _ = 3.00 x 10Bm/s, \f = c ED4 - PR EM f J ~ 7 ( 1 4. - I, = f (1 ± \ c ,, UB -UE, : u= 11. COM / "• 70 - -—7E=Ep 27r\/LC 11. COM E 0 sin(ife2: - w f), PRE MED 411 .CO MPRE M ED4 11. COM - PR EM ED4 f--4-R J — ^0 ) ) 0 2 111 j ~ 3~~T5 j ~5 da di f hi di m = — — — — ,, — h0 d0 c v — — ,, — ra -7 = ^" + "T' J A /2 — :Z? X vac n =T J ...
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This note was uploaded on 10/11/2011 for the course PHY 101 taught by Professor Ashkenkai during the Fall '08 term at FIU.

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