# Business stat hw#3 - X or Y={1,2,3,4,5,7,8,9 Y and X={7,9 4.4 6x4x3x3=216 options 4.6 10 = 3628800 4.8 a.26 b.30 c.22 4.10 a.13.28.03=.38

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Cameron Vollmuth Homework #3 4.1 (P1,P2),(P1,P3),(P1,P4),(P1,P5),(P1,P6),(P2,P3),(P2,P4),(P2,P5),(P2,P6),(P3,P4), (P3,P5),(P3,P6),(P4,P5),(P4,P6),(P5,P6) Sample Space= 15 If P1,P3,P5 have defects probability she chooses exactly one with a defect is 9/15 or 3/5. 4.2 X U Z= {1,2,3,4,5,7,8,9} X n Y= {7,9} X n Z={1,3,7} X U Y U Z= {1,2,3,4,5,7,8,9} X n Z n Y= {7} (X U Y) n Z= {1,2,3,4,7} (Y n Z) U (X n Y)= {2,4,7,9}

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Unformatted text preview: X or Y= {1,2,3,4,5,7,8,9} Y and X= {7,9} 4.4 6x4x3x3=216 options 4.6 10! = 3628800 4.8 a. .26 b. .30 c. .22 4.10 a. .13+.28-.03= .38 b. .16+.72-.04= .84 c. .16+.33=.49 d. .72 +.28= 1.0 4.11 This problem cannot be solved you need the joint number of a plane and a train in order to solve this problem. 4.12 a. 47% b. 31% c. 69% 4.13 a. 59% b. 86% c. 31% 4.15 a. 21 b. 17 c. 294 d. 680...
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## This note was uploaded on 10/06/2011 for the course BMGT 230 taught by Professor Studer-ellis during the Spring '08 term at Maryland.

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Business stat hw#3 - X or Y={1,2,3,4,5,7,8,9 Y and X={7,9 4.4 6x4x3x3=216 options 4.6 10 = 3628800 4.8 a.26 b.30 c.22 4.10 a.13.28.03=.38

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