Final Test

Final Test - B 5 [ ] 1 2 3 4 m1=m2=m, 5 min, 1= 2= . 10 zv...

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模模模模模模模模模模 B 模模模模模模 5 模模 [ 模模模√模模模模模 ] 1 模模模模模模模模模模模模模模模模模模模模模模模模 2 模模模模模模模模模模模模模模模模模模 3 模模模模模模模模模模模模模模模模模模模模模模模模 4 模模模模模模模模模模模模模模模模模模模模模模模模 m 1 =m 2 =m, α 1 = α 2 = α . 模模 5 模模模模模模模模模模模模模模模模模模模模模模模模 min , 模模 模模模模模模模模模模模模模模
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模模模模模模 10 模模 1 模模模模模模模模模模模模模模模模模模 ______________ 模模模模 ?_______________________________ 2 模模模模模模模模模模模模模 _______________,__________, _________________ 模 3 模模模模模模模 _______ 模模模模模模模模模模模模模 4 模模模模模模模模模模 _______________, 模模模模 _______________ 模 5 模模模模模模模模模模模模模模 ____________________ 模 β 3 cos / z z v = 模模模 , 模模模模模模模模模模 . 模模模模模模 模模模模模 模模模模模 . 模模模 1 2 1 2 12 sin sin δ = = Z Z i [ ] 1000 ϖ e A = s mm /
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模模模模模模 5 模模 1 模模“模模模模模 + 模模模模模≤模模模模模模模模”模模模模 模模模模模模模模模模 _______ 模 A 模模模模模模模模 B 模模模模模模 ; C 模模模模模模模 2 模模模模模模模模模 2 模模模模 ________ 模 A 模模模模模 ; B 模模模模模 ; C 模模模模模模 3 模模模模模模模模模模模模模模模模模模模 _______ 模 A 模模模 ; B 模模模模 ; C 模模模模模 4 模模模模模模模模模模模模模模 ________ 模 A 模模 p i =0; B 模模 p i =0, Σ M i =0; C 模 [e]=0, [mr]=0 模 5 模模模模模模模模模模模模模模模模模模模模模模模模模 ______ A 模模模模模 ; B 模模模模模模模 ; C 模模模模模模模 C B A B B
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模模模模模模 15 模模 1 模模模模模模模模模模模模模模模模模模模模模模模模 2 模模模模模模模模模′模模模模模模模模模模模模模模模 模模模模模模 模模模模模模模模模模 3 模模模模模模模模模模模模模模模模模模模模模模模模模模模模模模模模模 4 模模模模模模模模模模模模模模模模模模模模模模模模模
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模模模模模模 22 模模 1 模模模模模模模模模模模模模模模模模模模模 , ω 1 模 模模 1 模模模模模模模模 P 14 ; 模 2 模模模 1 模 4 模模模模 模模模模模模模 6 模模 A B D C 1 2 4 3 5 P 15 P 45 P 13 P 34 P 14 模模 i 14 = ϖ 1 / ϖ 4 = P 14 P 34 / P 14 P 1 5 1 2 5 3 4
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2 模模模模模模模模模模模模模模模模模模模模模模 : (1) 模模模模模模模 r 0 ; (2) 模模模模模模模 s 模模模模 ; (3) 模模模模模模模 模模模模模模模模模模模模模模 45 0 模模模模模模模模模 s’ 模模模模模 模模’ 模模 6 模模 ϖ 1 1 2 3 r 0 s δ α = 0 F v s’ δ 45 o
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This note was uploaded on 10/10/2011 for the course ME 04106 taught by Professor Shen during the Spring '10 term at Tongji.

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Final Test - B 5 [ ] 1 2 3 4 m1=m2=m, 5 min, 1= 2= . 10 zv...

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