Chap6_exercise

Chap6_exercise - 6 1 IB0 IC0 UBE0 IC IB IBS > IB > 0 UCEUBE...

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6 - 1 ---------------------- --- I B ≈0 - I C ≈0 - U BE ≤0 ------------ --- I C - βI B ------------ I BS > I B > 0 --- U CE ≤U BE ----------- I B > I BS
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----------- -- I BS - E C - βR C - 5 - 40×2 0.0625mA I B = (5 - U BE )/ R B = (5 - 0.7)/ 100 = 0.043mA I B < I BS - T ------ 6 - 2 2K U O - 5V 100K β=40
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-- I BS - E C - βR C - 5 - 50×2.2 0.045mA I B = (5 - U BE )/ R B = (5 - 0.7)/ 47 = 0.1mA 2.2K U O - 5V 47K β=50 I B > I BS - T ------
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-- U I = 0 I B - 0 I C - 0 T ------ U I = 3V I BS - E C - βR C - 5 - 35×2.5 0.057mA I B = (U I - U BE )/ R B = (3 - 0.7)/ 30 = 0.077mA 2.5K U O - 5V 30K U I β=35 0 3 I B > I BS - T ------
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1K U O - 12V 1.5K U I - 12V 18K -- U I =0 - ----- U BE <0 I B ≈0 I C ≈0 T ------ U I =3V - I BS - 12 - βR C - 12 - 30×1 - 0.4mA 2 BE 1 BE I R ) 12 ( U R U U - - - - = I B = I 1 - I 2 = 1.53 - 0.705 = 0.828mA I B > I BS - T ------- β=30
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Chap6_exercise - 6 1 IB0 IC0 UBE0 IC IB IBS > IB > 0 UCEUBE...

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