Pre-Calculus Practice Problem 61

# Pre-Calculus Practice Problem 61 - -1 = 0 a Factor P x...

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Unit 2, Activity 3, The Zeros of Polynomials with Answers Blackline Masters, Advanced Math-PreCalculus Page 59 Louisiana Comprehensive Curriculum, Revised 2008 This is a non-calculator exercise. 1. If 12 11 2 ) ( 2 3 + = x x x x P , a) Show that x + 3 is a factor of P ( x ), Using synthetic division P(-3)=0 so by the factor theorem (x + 3) is a factor b) Find Q ( x ), if P ( x ) = ( x + 3) Q ( x ), The depressed equation left from part (a) is Q(x). 4 5 ) ( 2 + = x x x Q 2. If 8 2 5 ) ( 2 3 + + = x x x x P and P
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Unformatted text preview: (-1) = 0, a) Factor P ( x ) completely. (x + 1)(x – 2)(x – 4) b) Write the solutions of P( x ) = 0. P(x) = 0 for x = -1, 2, and 4 c) Sketch the graph of P ( x ) 3. If 2 3 ) ( 2 3 + + − = x x x x P and (x – 2) is a factor of P(x), a) Find Q ( x ), if P ( x ) = ( x – 2) Q ( x ) and 1 ) ( 2 − − = x x x Q b) Find the zeros of P( x ). Exact values please! P(x) = 0 for x = 2 5 1 , 2 5 1 , 2 − +...
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