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Pre-Calculus Practice Problem 98

# Pre-Calculus Practice Problem 98 - x = 3ln x has a zero at...

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Unit 3, Activity 4, Translations, Dilations, and Reflections of Ln x with Answers Blackline Masters, Advanced Math-Pre-Calculus Page 96 Comprehensive Curriculum, Revised 2008 My Opinion Statement If you disagree why? Calculator Findings 1. The graph of f ( x ) = ln( x + 3) is translated 3 units to the right. The zero is at (4, 0). This graph is translated 3 units to the left. The zero will be at (-2, 0). 2. The graph of f ( x ) = ln(- x ) is reflected over the y -axis. The domain is (- , 0). The statement is correct. 3. The graph of f
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Unformatted text preview: x ) = 3ln( x ) has a zero at x = 3. The value 3 causes a dilation. The zero stays at x = 1. 4. The graph of f ( x ) = ln(4 – x ) has been reflected over x = 4. Its domain is { x : x < 4} The statement is correct. 5. The graph of f ( x ) = ln( x ) + 2 has a zero at e-2 . The graph of f(x) is translated 2 units up. The zero is e − ≈ 2 1353 . ... Let f(x) = 0 then ln x = -2 so e x − = 2 6. The graph of f ( x ) = ln( x – 4) has a vertical asymptote at x = 4 and a zero at x = 5. The statement is correct....
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