Unformatted text preview: x ) = 3ln( x ) has a zero at x = 3. The value 3 causes a dilation. The zero stays at x = 1. 4. The graph of f ( x ) = ln(4 – x ) has been reflected over x = 4. Its domain is { x : x < 4} The statement is correct. 5. The graph of f ( x ) = ln( x ) + 2 has a zero at e2 . The graph of f(x) is translated 2 units up. The zero is e − ≈ 2 1353 . ... Let f(x) = 0 then ln x = 2 so e x − = 2 6. The graph of f ( x ) = ln( x – 4) has a vertical asymptote at x = 4 and a zero at x = 5. The statement is correct....
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This note was uploaded on 10/10/2011 for the course MAC 1147 taught by Professor German during the Fall '08 term at University of Florida.
 Fall '08
 GERMAN
 Calculus, PreCalculus

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