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Unformatted text preview: Schaum’s Outline , Chapter 7: work Problem 16. As above, if a limit fails to exist you should describe what does happen. Challenge Problems: Consider the function V ( x ) =  x2  . 1. De±ne a new function f ( x ) = V ( x )V (1) x1 Compute lim x → 1 f ( x ). If the limit does not exist, explain why as above. 2. De±ne a new function g ( x ) = V ( x )V (2) x2 Compute lim x → 2 g ( x ). If the limit does not exist, explain why as above. 1 Hints and Answers Exercises: 1. The online textbook provides answers to most problems in Appendix A. In cases where the limit does not exist: 11) vertical asymptote. Also correct to say the (one sided) limit is infnity 18c) lim x → + f ( x ) =1, but lim x →f ( x ) =2. 2. Answers are aFter the problem in Schaum’s Challenges: 1.1. 2. DNE. lim x → + g ( x ) = 1, but lim x →g ( x ) =1. 2...
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 Fall '08
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 Calculus, Algebra, Limits, Limit, Limit of a function, Schaum

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