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Unformatted text preview: (d) How high is it when its velocity is48 ft/s? 1 6. The graph of f ( x ) = 1 /x has a tangent line that passes through (0 , 1 . 5) as shown at right. (a) Where is the point of tangency? (b) Find the equation of the tangent line at the point (2 , . 5). Sketch this line in the graph at right. –1 –0.5 0.5 1 1.5 2 –1 1 2 3 4 x Challenge Problems: 1. In the ±gure the below the curve is y = sin x and the line is tangent to the curve at x = 3 π/ 4. Find the xintercept of the line. 2 2. In the fgure the below the curve is y = sin x and the tangent line has xintercept at 5 π/ 4. Find the point o± tangency. Hints and Answers Exercises: 1. All Type 1. 2. All Type 2. (a) x = 1 / 5; (b) x =1 ± √ 2; (c) x =2 ,4. 3. Type 2. 4. Type 1. 5. (a) Type 1,64 ±t/s; (b) Type 2, 1.875 s; (c) Type 1,80 ±t/s; (d) Type 2, 64 ±t. 6. (a) Type 2, (4 / 3 , 3 / 4); (b) Type 1, y =x/ 4 + 1. Challenge: 1. Type 1, x = 3 π/ 4 + 1 ≈ 3 . 356. 2. Type 2, x ≈ 2 . 063. 3...
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 Fall '08
 STAFF
 Calculus, Derivative, Slope, secant slope, 2 seconds, 48 ft

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